使用指针输出结构体变量stu的成员name之值

#include<stdio.h>
int main(void)
{
struct student
{
int num;
char name[10];
float score[3];
} stu = {2012, "WuHua", {75.4f, 80, 92}};
struct student *ptr;

3 分

printf("%s\n", 3

); /* 必须使用指针变量ptr实现 */

return 0;

}

#include<stdio.h>
int main(void)
{
struct student
{
int num;
char name[10];
float score[3];
} stu = {2012, "WuHua", {75.4f, 80, 92}};
struct student *ptr;

ptr = &stu;

printf("%s\n", ptr->name);

return 0;
}

一个实现,如下:

#include<stdio.h>
int main(void)
{
struct student
{
int num;
char name[10];
float score[3];
} stu = {2012, "WuHua", {75.4f, 80, 92}};
struct student *ptr = &stu;



printf("%s\n", ptr->name); 

return 0;
}

您好,我是有问必答小助手,您的问题已经有小伙伴帮您解答,感谢您对有问必答的支持与关注!
PS:问答VIP年卡 【限时加赠:IT技术图书免费领】,了解详情>>> https://vip.csdn.net/askvip?utm_source=1146287632