上课教了用Python的星号画钻石,但我不知道怎么画数字(是要用星号画一个很大的数字)
你题目的解答代码如下:
def number(n):
print(" ***** " if n in [0,2,3,5,6,7,8,9] else " ")
for i in range(3):
print("*" if n in [0,4,5,6,8,9] else " ",end="")
print(" ",end="")
print("*" if n in [0,1,2,3,4,7,8,9] else " ")
print(" ***** " if n in [2,3,4,5,6,8,9] else " ")
for i in range(3):
print("*" if n in [0,2,6,8] else " ",end="")
print(" ",end="")
print("*" if n in [0,1,3,4,5,6,7,8,9] else " ")
print(" ***** " if n in [0,2,3,5,6,8,9] else " ")
for i in range(10):
number(i)
print()
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不知道有没有对应的库, 我手动做了一个数字。只有6的形状
供参考
val_num_dict = {6:['*******','* ','* ','*******','* *','* *','*******']}
val_n = 6
for c in val_num_dict[val_n]:
print(c)