#include
using namespace std;
int main()
{
int k[11];
int i, a, n, s;
for (a=2;a<=1000;a++)
{
n = 0;
s = a;
for (i = 1; i < a; i++)
if ((a % i) == 0)
{
n++;
s = s - i;
k[n] = i;
}if (s == 0)
{
cout << a << "is a 完数" << endl;
cout << "its factors are:";
for (i = 1; i < n; i++)
cout << k[i] << " ";
cout << k[n] << endl;
}
}
return 0;
数组太小.改大点即可
int k[1001];
你题目的解答代码如下:
#include <iostream>
using namespace std;
int main()
{
int k[1001]; //数组长度改大点
int i, a, n, s;
for (a = 2; a <= 1000; a++)
{
n = 0;
s = a;
for (i = 1; i < a; i++)
if ((a % i) == 0)
{
n++;
s = s - i;
k[n] = i;
}
if (s == 0)
{
cout << a << "is a 完数" << endl;
cout << "its factors are:";
for (i = 1; i < n; i++)
cout << k[i] << " ";
cout << k[n] << endl;
}
}
return 0;
}
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if(s==0)放到上一个if代码块中
int main()
{
int k[11];
int i, a, n, s;
for (a=2;a<=1000;a++)
{
n = 0;
s = a;
for (i = 1; i < a; i++)
if ((a % i) == 0)
{
n++;
s = s - i;
k[n] = i;
if (s == 0)
{
cout << a << "is a 完数" << endl;
cout << "its factors are:";
for (i = 1; i < n; i++)
cout << k[i] << " ";
cout << k[n] << endl;
}
}
}
return 0;
}
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