请问python如何找出两个列表中具有相同‘姓名’键的字典,并把具有相同'姓名'键字典的id作为键值对输出到新的列表的字典

有两个列表：

l1 = [{id:'001',name:'john'},{id:'002',name:'jim'},{id:'003',name:'jack'},{id:'004',name:'jerry'}]
l2 = [{id:'005',name:'john'},{id:'006',name:'jim'}]

输出结果：

l3 = [{'001':'005'},{'002':'006'}]

请问如何编写？

这样？

l1 = [{'id':'001','name':'john'},{'id':'002','name':'jim'},{'id':'003','name':'jack'},{'id':'004','name':'jerry'}]
l2 = [{'id':'005','name':'john'},{'id':'006','name':'jim'}]
l3=[]
for item in l1:
    l=[x for x in l2 if x['name']==item['name']]

    if len(l)>0:
        newitem={}
        newitem[item['id']]=l[0]['id']
        l3.append(newitem)

print(l3)

使用列表解析式简洁写法：

l1 = [{'id':'001','name':'john'},{'id':'002','name':'jim'},{'id':'003','name':'jack'},{'id':'004','name':'jerry'}]
l2 = [{'id':'005','name':'john'},{'id':'006','name':'jim'}]
res=[{k1['id']:k2['id']} for k1 in l1 for k2 in l2 if k2['name']==k1['name']]
print(res)
#输出：
[{'001': '005'}, {'002': '006'}]

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