从键盘中输入一个自变量x,求分段函数y=f(x)的值,f(x)的表达式如下
x+3,x>5
y=0,0<=x<=5
2X+30,x<0
#include<stdio.h>
#include<math.h>
int main()
{
float x, f;
printf("请输入x的值:");
scanf("%f", &x);
if(x > 5)
f = x + 3;
else if(x >= 0 && x <= 5)
f = 0;
else
f = 2 * x + 30;
printf("f(X)的值为%.2f", f);
return 0;
}
感谢,点个采纳呗;;;
十分感谢