python编程求s=2+3+4+……,大于20000的最小值
for i in range(10,10000): if sum(range(2,i)) > 20000: print(sum(range(2,i))) break
示例代码如下有帮助望采纳~
有帮助望采纳~
result = 0 start = 2 while result <= 20000: result += start start += 1 print(result)