编写一个java程序,求一元二次方程ax²+bx+c=0的根,并用相关数据测试
import java.util.Scanner;
import static java.lang.String.format;
public class Max {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("a");
double a = sc.nextDouble();
System.out.println("b");
double b = sc.nextDouble();
System.out.println("c");
double c = sc.nextDouble();
double daierta = Math.pow(b, 2) - 4 * a * c;
double x1 = 0.0;
double x2 = 0.0;
if (daierta == 0.0) {
x1 = (-b + Math.sqrt(daierta)) / (2 * a);
System.out.println(format("x为%s", x1));
} else if (daierta > 0.0) {
x1 = (-b + Math.sqrt(daierta)) / (2 * a);
x2 = (-b - Math.sqrt(daierta)) / (2 * a);
System.out.println(format("x1的值%s,x2的值为%s", x1, x2));
} else {
System.out.println("无解!!!");
}
}
}
很简单啊,套公式。