题目:牛客价值序列
#include<bits/stdc++.h>
#define int long long
using namespace std;
const int mod=998244353;
int T,n,ans,a[100010],p2[100010];
void solve()
{
ans=1;
memset(a,0,sizeof a);
cin>>n;
for(int i=1;i<=n;i++)cin>>a[i];
for(int i=1;i<=n;i++)
{
int j=i;
while(j<n&&a[j]==a[j+1])j++;
if((i>1)&&(j<n)&&((a[i]>a[i-1]&&a[j]<a[j+1])||(a[i]<a[i-1]&&a[j]>a[j+1])))
ans=ans*p2[j-i+1]%mod;
else ans=ans*(p2[j-i+1]-1+mod)%mod;
i=j;
}
cout<<ans<<endl;
}
signed main()
{
p2[0]=1;
for(int i=1;i<=100000;i++)p2[i]=2*p2[i-1]%mod;
ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
cin>>T;
while(T--)
solve();
}