用c++显示学生成绩

用c++表示学生的输出成绩,≥90为优秀,80到89为良,70到79为中,60到69为及格,60之下为不及格


#include "stdafx.h"
#include<iostream>
using namespace std;
void main()
{
int score;
cout << "请输入成绩:" << endl;
cin >> score;
if (score > 100)
cout << "成绩输入有误,重新输入!" << endl;
else if (score >= 90 && score <= 100)
cout << "成绩等级为:优秀" << endl;
else if (score >= 80 && score < 90)
cout << "成绩等级为:良" << endl;
else if (score >= 70 && score <80)
cout << "成绩等级为:中" << endl;
else if (score >= 60 && score < 70)
cout << "成绩等级为:及格" << endl;
else
cout << "成绩等级为:不及格" << endl;
}

感谢采纳!