python如何循环历遍这2个列表？

python用什么方法可以循环历遍这三个列表？图2是要实现的效果。

u1 = ["稳健的", "赢,赢得", "携带,扛", "如此", "如此匆忙", "愚蠢的", "野兔",
      "意思是", "龟", "骄傲的", "不小心的", "悲伤的", "耐心的", "更努力的"]
u2 = ["另一个", "碰撞", "到;到上", "地面", "死", "捡起", "容量的",
      "他自己", "从那时起", "停止", "整天", "出现", "努力吧, 加油"]
u3 = ["困难的", "青蛙", "袋鼠", "轮回", "海洋", "海星", "非洲", "老虎",
      "亚洲", "被称为", "狮子", "熊猫", "象", "长颈鹿", "脖子", "树叶"]

all = locals()  # locals() 函数会以字典类型返回当前位置的全部局部变量。
need_visited_list = ['u1', 'u2', 'u3']  # 需要遍历数组的变量名
for name in need_visited_list:
    # 得到需要遍历数组的变量名
    print("---------%s------" % name)
    for item in all[name]:  # 根据变量名找到对应的变量，进行遍历
        print("%s\n*********" % item)
    print()  # s输出一个空行

for x in chain(u1,u2,u3):
    print(x)

for k,v,p in zip(u1,u2,u3):
    print(k,v,p)

zip函数可以遍历,但是你的三个列表要一样长

```python
a=[1,2,3,4,5]
b=[7,8,9,10,11]
c=['a','b','c','d']
#变成一个列表开始循环
x=a[:]+b[:]+c[:]
#列表可以相加
# for i in x:
#     print(i)

# for i in  iter(a+b+c):
#     print(i)

# def forloop(*args):
#     for i in args:
#         yield from i


# for i in forloop(a,b,c):
#     print(i)

```

题主用zip即可：如下

for u_1,u_2,u_3 in zip(u1, u2,u3):
    print(u_1,u_2,u_3)

把3个列表按最长的，都补充到一样长，补0即可，然后zip循环，循环完成把你的结果中的0匹配删掉。