Python 中的 map

classes = [
  {"name": "n_1", "age": 24, "grade": "A"},   {"name": "n_2", "age": 23, "grade": "B"},   {"name": "n_3", "age": 28, "grade": "A"},   {"name": "n_4", "age": 24, "grade": "A"},   {"name": "n_5", "age": 25, "grade": "C"},   {"name": "n_6", "age": 21, "grade": "D"},   {"name": "n_7", "age": 27, "grade": "A"},]
通过map函数将上述同学的age + 1(对原数据结构有影响, 尽量不要用lambda)

参考：

for c in classes:
    c["age"] = c["age"] + 1

结果：

[{'name': 'n_1', 'age': 25, 'grade': 'A'}, {'name': 'n_2', 'age': 24, 'grade': 'B'}, {'name': 'n_3', 'age': 29, 'grade': 'A'}, {'name': 'n_4', 'age': 25, 'grade': 'A'}, {'name': 'n_5', 'age': 26, 'grade': 'C'}, {'name': 'n_6', 'age': 22, 'grade': 'D'}, {'name': 'n_7', 'age': 28, 'grade': 'A'}]

img

先使用map函数调用自定义转换函数，然后再将map对象转成列表即可：

classes = [{"name": "n_1", "age": 24, "grade": "A"},{"name": "n_2", "age": 23, "grade": "B"},{"name": "n_3", "age": 28, "grade": "A"},{"name": "n_4",  "age": 24, "grade": "A"},{"name": "n_5", "age": 25, "grade": "C"},{"name": "n_6", "age": 21, "grade": "D"},{"name": "n_7", "age": 27, "grade": "A"},]
def fun(c: dict):
    c['age'] = c['age'] + 1
    return c
res=list(map(fun, classes))
print(res)

如有帮助，请点采纳。

def ageadd(x:dict):
    x['age']+=1
    return x
classes = [
  {"name": "n_1", "age": 24, "grade": "A"},   {"name": "n_2", "age": 23, "grade": "B"},   {"name": "n_3", "age": 28, "grade": "A"},   {"name": "n_4", "age": 24, "grade": "A"},   {"name": "n_5", "age": 25, "grade": "C"},   {"name": "n_6", "age": 21, "grade": "D"},   {"name": "n_7", "age": 27, "grade": "A"},]
map(ageadd,classes)
print(classes)

img


有帮助请点一下右上角的采纳,谢谢

私以为无解，map需要导入一个函数，而你这是非标函数，必须自己定义一个。
还有种方法是拆成列表，对列表+1在组回去。

您好，我是有问必答小助手，您的问题已经有小伙伴帮您解答，感谢您对有问必答的支持与关注！
PS：问答VIP年卡 【限时加赠：IT技术图书免费领】，了解详情>>> https://vip.csdn.net/askvip?utm_source=1146287632