新手上路。输出100以内所有个位数为六 且能被三整除的自然数 并计它们的个数

。

#include<stdio.h>
int main() 
{
    int i=0；
    int count = 0;      //count用于计数
    for (i = 0; i <= 100; i++)
    {
        if (i%10==6&&i%3==0)
        {
            count++;   //条件满足，个数加一
        }
    }
    printf("个数：%d\n", count);
}

int main() {
    int i, count = 0;
    for (i = 0; i < 101; i++) {

        if (i%10==6&&i%3==0)
        {
            count++;
        }
    }

    printf("符合条件的个数是%d", count);
}

for(i=1;i<=100;i++)
{
if(i%10==6 && i%3==0)
printf("%d ",i);
}

public static void main(String[] args) {
        int count = 0;
        for (int i = 1;i < 100;i++) {
            if (i % 6 == 0 && (i) % 10 == 6) {
                count ++;
            }
        }
        System.out.println(count);
    }

//============================================================================
// Name        : csdn.cpp
// Author      : jshand
// Version     :
// Copyright   : Your copyright notice
// Description : Hello World in C++, Ansi-style
//============================================================================

#include <iostream>
using namespace std;

int main() {
    int count= 0;
    for (int i = 0; i < 100; ++i) {

        if((i%10) == 6  && i%3 == 0){
            cout << "hello: " << i<< "/6:" << (i/6)  << "\t"
                                     << i<< "%10:" << (i%10) <<"\t"
                            << endl;
            count++;
        }

    }
    cout << " count= " << count <<  endl;
    return 0;
}