输入一个矩阵(5*5),求矩阵下三角形元素之和
#include <stdio.h>
int main()
{
const int n = 5;
int a[n][n];
for (int i = 0; i < n; i++)
for (int j = 0; j < n; j++)
scanf("%d", &a[i][j]);
int sum = 0;
for (int i = 0; i < n; i++)
for (int j = 0; j <= i; j++)
sum += a[i][j];
printf("%d", sum);
return 0;
}