PTA1014福尔摩斯的约会

求大佬帮忙看一下，这个是只有10分

#include <stdio.h>
int main()
{
    int i,j,k=0,l=0;
    char s[4][60],a[2],D[7][10]={"MON","TUE","WED","THU","FRI","SAT","SUN"};
    for(i=0;i<4;i++)
    {
        for(j=0;j<60;j++)
        {
            scanf("%c",&s[i][j]);
            if(s[i][j]=='\n')
                break;
        }
    }
    for(i=0;;i++)
    {
        if(s[0][i]=='\n'||s[1][i]=='\n')
            break;
        if((s[0][i]>='a'&&s[0][i]<='z')||(s[0][i]>='A'&&s[0][i]<='Z')){
            if(s[0][i]==s[1][i]){
                a[k]=s[0][i];
                k++;
            }
        }
        if(k==2)
            break;
    }
    for(i=0;i<60;i++){
        if(s[2][i]=='\n'||s[3][i]=='\n')
            break;
        if((s[2][i]>='a'&&s[2][i]<='z')||(s[2][i]>='A'&&s[2][i]<='Z')){
            if(s[2][i]==s[3][i]){
                l=i;
                break;
            }
        }
    }
    printf("%s ",D[a[0]-'A']);
    if(a[1]>='0'&&a[1]<='9')
        printf("%02d:",a[1]-'0');
    else
        printf("%02d:",a[1]-'A'+10);
    printf("%02d",l);
    return 0;
}

#include <stdio.h>
#include <ctype.h>

int main()
{
    const char *days[] = {"MON", "TUE", "WED", "THU", "FRI", "SAT", "SUN"};
    char a[4][61];
    for (int i = 0; i < 4; i++)
        scanf("%s", &a[i][0]);
    const char *p = &a[0][0];
    const char *q = &a[1][0];
    int i = 0;
    while (*p && *q)
    {
        if (*p == *q && isalpha(*p))
        {
            if (i == 0)
            {
                printf("%s ", days[*p - 'A']);
                i++;
            }
            else
            {
                printf("%02d:", *p - 'A' + 10);
                break;
            }
        }
        p++;
        q++;
    }
    p = &a[2][0];
    q = &a[3][0];
    while (*p && *q)
    {
        if (*p == *q && isalpha(*p))
        {
            printf("%02d", (int)(p - &a[2][0]));
            break;
        }
        p++;
        q++;
    }
    return 0;
}