我是tab效果,当选中效果class="trol active"的时候,dot增加pitch类名
否则pitch消失。
选中状态class=“active”
原始:
<div class="dot">
<span>1</span>
<span>2</span>
<span class="trol">3</span>
<span>4</span>
</div>
效果:
<div class="dot pitch">
<span>1</span>
<span>2</span>
<span class="trol active">3</span>
<span>4</span>
</div>
<script src="http://code.jquery.com/jquery-migrate-1.2.1.min.js"></script>
<script>
var int = self.setInterval("clock()", 1000);
function clock() {
if ($(".trol").hasClass("active")) {
$(".dot").addClass("pitch");
}else{
$(".dot").removeClass("pitch");
}
}
</script>
这个问题我之前看到过很多次,都是你提问的吗,怎么一直在问这个
var trol = document.getElementByClassName('trol')[0]
var dot = document.getElementByClassName('dot')[0]
if(trol.classList.indexOf("active")){
dot.classList.add('pitch')
}else{
dot.classList.remove('pitch')
}
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那不就是你选中的事件后再追加trol 的样式,用addClass就不可以了?
标签添加id
<span id = "myspan"class="trol active">3
自定义class
.myclass{
}
获取标签对象,并添加class
var myspan = document.getElementById("myspan");
myspan.className="myclass";
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8" />
<meta http-equiv="X-UA-Compatible" content="IE=edge" />
<meta name="viewport" content="width=device-width, initial-scale=1.0" />
<title>Document</title>
</head>
<body>
<div class="dot">
<span class="active">A</span>
<span>B</span>
<span class="trol">C</span>
<span>D</span>
</div>
<script src="https://cdn.staticfile.org/jquery/3.6.0/jquery.min.js"></script>
<script>
$('.dot').delegate('span', 'click', function(e) {
$(this).addClass('active').siblings().removeClass('active')
if ($(this).hasClass('trol')) {
$('.dot').addClass('pitch')
} else {
$('.dot').removeClass('pitch')
}
})
</script>
</body>
</html>
这个问题是一样的,<div class="dot">
<span>1</span>
<span>2</span>
<span class="trol">3</span>
<span>4</span>
</div>
<script>
var oDiv = document.querySelector(".dot");
var lis = oDiv.getElementsByTagName("span");
for(var i=0;i<lis.length;i++){
lis[i].index = i;
lis[i].onmouseover = function(){
removeclass(this.index)
if (this.getAttribute('class') .indexOf('trol') > -1) {
document.querySelector('.dot').classList.add("pitch");
}
else{
document.querySelector('.dot').classList.remove("pitch");
}
}
}
function removeclass(index){
for(var i=0;i<lis.length;i++){
if(i==index){
lis[i].classList.add("active");
}
else{
lis[i].classList.remove("active");
}
}
}
</script>
选中trol后在它的父级增加类就可以了啊
基于问题, 代码如下
window.onload = function() {
var trol = document.querySelector('.trol');
var dot = document.querySelector('.dot');
var span = document.querySelectorAll('.dot span');
for(var i = 0; i < span.length; i++) {
var item = span[i];
item.onclick = function() {
if(trol && trol.classList.indexOf("active") > -1){
dot.classList.add('pitch');
} else {
trol.classList.remove('active');
dot.classList.remove('pitch');
}
}
}
}
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