数字折叠相加的问题怎么做

#include <stdio.h>
#include <math.h>

int reverse(int n)
{
    int r = 0;
    while (n)
    {
        r = r * 10 + n % 10;
        n /= 10;
    }
    return r;
}

int main()
{
    int n, m, b;
    scanf("%d", &n);
    m = (int)log10(n) + 1;
    b = (int)pow(10, (m + 1) / 2);
    printf("%d", n / b + reverse(n % b));
    return 0;
}