编写一个函数,输入 n 为偶数时,调用函数求 1/2+1/4+到+1/n, 当输入 n 为奇数时,调 用函数 1/1+1/3+……1/n
#include<stdio.h>
float sum(int n){
float a=0,b=0;
int i;
int t,p;
if(n%2==0){
for(i=2;i<=n;i+=2){
t=i;
a=a+1/t*1.0;
}
return a;
}
else{
for(i=1;i<=n;i+=2){
p=i;
b=b+1/p*1.0;
}
return b;
}
}
int main(){
int n;
printf("请输入n的值");
scanf("%d",&n);
printf("该数列的和为%f",sum(n));
return 0;
}
#include <stdio.h>
float sum(int n)
{
float a = 0, b = 0;
int i;
int t, p;
if (n % 2 == 0)
{
for (i = 2; i <= n; i += 2)
{
t = i;
a = a + 1.0 / t;
}
return a;
}
else
{
for (i = 1; i <= n; i += 2)
{
p = i;
b = b + 1.0 / p;
}
return b;
}
}
int main()
{
int n;
printf("请输入n的值");
scanf("%d", &n);
printf("该数列的和为%f", sum(n));
return 0;
}
#include<stdio.h>
float sum(int n) {
float a = 0, b = 0;
int i;
int t, p;
if (n % 2 == 0) {
for (i = 2; i <= n; i += 2) {
t = i;
a = a + 1.0 / (float)t * 1.0; //改动点1
}
return a;
}
else {
for (i = 1; i <= n; i += 2) {
p = i;
b = b + 1.0 / (float)p * 1.0; //改动点1
}
return b;
}
}
int main() {
int n;
printf("请输入n的值");
scanf("%d", &n);
printf("该数列的和为%f", sum(n));
return 0;
}