无法获得预期的输入结果，预期输入8时获得7，但结果仍然为8，如何解决？

问题：题目:有n个人围成一圈,顺序排号,从第一个开始报数(从1到3报数),凡报到3的人退出圈子,问最后最后留下的是原来第几号的那位.

问题相关代码，请勿粘贴截图

#include <stdio.h>
int main()
{    int i,j,k=0,l=0,m=0,A[50];
    printf("How many ?\n");
    scanf("%d",&i); 
    for(j=0;j<i;j++) 
    *(A+j)=j+1;
    while(m<i-1)
    {if(A[l]!=0) k++;
     if(k%3==0)
        {A[l]=0;
         k=0;
         m++;}
        l++;
     if(l==i) l=0;    
    }
    while(A[l]==0) l++;
    printf("%d",A[l]);
    return 0;
}

运行结果及报错内容

我的解答思路和尝试过的方法

我想要达到的结果

试试这个

#include<stdio.h>
#include<malloc.h>
struct node

{
    int num;

    struct node *next;

};

struct node *head;

struct node *last;

void cre_list()

{
    head = (struct node *)malloc(sizeof(struct node));

    last = head;

    head->next = head;

}

void display_node()

{
    struct node *ptr = head->next;

    while(ptr != head)

    {
        // printf("%d\t",ptr->num);

        ptr = ptr->next;

    }

    //printf("\n");

}

void add_node(int num)

{
    struct node *ptr = (struct node *)malloc(sizeof(struct node));

    ptr->num = num;

    ptr->next = head;

    last->next = ptr;

    last = ptr;

}

void rev_node()

{
    struct node *ptr = head;

    last->next = head->next;

    head = head->next;

    free(ptr);

}

void tiren_node()

{
    struct node *ptr = head;

    struct node *str = ptr->next;

    struct node *qtr = str->next;

    while(ptr->next != ptr)

    {
        str = ptr->next;

        qtr = str->next;

        str->next = qtr->next;

        ptr = str->next;

    }

    printf("%d",ptr->num);

}

int main()

{
    int i = 0;

    cre_list();

    int n;

    //printf("please input n:\n");
    printf("How many ?\n");

    scanf("%d",&n);

    // printf("%d\n",n);

    for(i = 1; i <= n; i++)

    {
        add_node(i);

    }

    display_node();

    rev_node();

    tiren_node();

    return 0;

}

其实题主思路还是不错的，不过其实这道题可能没有想象的那么麻烦

#include <stdio.h> 

int x = 3; //报到3退出

int main() 
{ 
    int m,n = 0; 
    scanf("%d", &m); 
    for (int i = 2; i <= m; ++i) 
        n = (n+x)%i; //循环取模 
    printf("%d\n", n+1);  //找到后加上除循环外本来那一位 就是原来第几号的那位
    return 0; 
}

希望对题主有所帮助，可以的话还请点下采纳！