/c10-2-10/
#include<stdio.h>
#define N 10
void fun(char str1[],char str2[])
{
int i,j;
j=0;
for(i=0;str1[i]!='\0';i=i+2)
{
str2[j]=str1[i];
j=j+1;
}
for(i=0;str2[i]!='\0';i++)
printf("%c",str2[i]);
}
int main()
{
char a[N],b[N]={0};
printf("请输入一串字符:");
gets(a);
fun(a,b);
return 0;
}
#include<stdio.h>
#define N 10
void fun(char str1[], char str2[])
{
int i, j;
j = 0;
str2[N] = { 0 };
for (i = 0; str1[i] != '\0'; i = i + 2)
{
str2[j] = str1[i];
j = j + 1;
}
str2[j] = '\0';
for (i = 0; str2[i] != '\0'; i++)
printf("%c", str2[i]);
}
int main()
{
char a[N] = {0}, b[N];
printf("请输入一串字符:");
gets(a);
fun(a, b);
return 0;
}
判断输入的字符串长度是否等于1;等于1会乱码
#include<stdio.h>
#include<string.h>
#define N 10
void fun(char str1[],char str2[])
{
int i,j;
j=0;
for(i=0; str1[i]!='\0'; i=i+2)
{
str2[j]=str1[i];
j=j+1;
}
for(i=0; str2[i]!='\0'; i++)
printf("%c",str2[i]);
}
int main()
{
char a[N],b[N]= {0};
printf("请输入一串字符:");
gets(a);
if(strlen(a)==1)
{
printf("%c",a[0]);
return 1;
}
else
{
fun(a,b);
}
return 0;
}
没啥问题啊