4、编写程序求满足1+2+3+4+…+n>=10000的最小的正整数n为多少
public class Main {
public static void main(String[] args) {
int n=0,sum=0;
while (sum<10000){
n++;
sum+=n;
}
System.out.println(n);
}
}
你题目的解答代码如下:
import java.util.*;//导包
public class HelloWorld {
public static void main(String []args) {
int n = 0;
int sum = 0;
while (sum<10000){
n++;
sum += n;
}
System.out.println(n);
}
}
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public class abcd {
public static void main(String args[]){
int i,j;
int sum=0;
for(i=1;i<=8888;i++)
{
sum=sum+i;
}
System.out.println("最大数和为"+sum);
System.out.println("n="+i);
}
}
import java.util.*;
public class a {
public static void main(String args [ ]) {
int i,sum = 0;
for( i = 1 ; i > 0 ; i++) {
sum = sum +i;
if( sum >= 10000)
break;
}
i = i-1;
System.out.println("最大整数:"+i);
}
}
/*参考https://blog.csdn.net/weixin_46106870/article/details/108699230?utm_source=app&app_version=4.21.0&code=app_1562916241&uLinkId=usr1mkqgl919blen*/
int sum=0
int a=1
for(int i=0,i++,i<=10000){
sum=sum+a
if(sum>=10000){
print(a)
}
a=a+1
}
https://ask.csdn.net/questions/7617681?answer=53646278&spm=1001.2014.3001.5504
一模一样的问题,提问前部能先自己思考一下