C语言编写一个函数totsubstrnum(char*str,char*substr),它的功能是：统计字符串substr在字符串str中出现的次数

编写一个函数totsubstrnum(charstr,charsubstr),它的功能是：统计字符串substr在字符串str中出现的次数

#include<stdio.h>
int count(char*str,char*substr)
{
    int i,j,k,num=0;
    for(i=0; str[i]!='\0'; i++)
        for(j=i,k=0; substr[k]==str[j]; k++,j++)
            if(substr[k+1]=='\0')
            {
                num++;
                break;
            }
    return(num);
}
int main()
{
    char str[80],substr[80];
    int n;
    gets(str);
    gets(substr);
    printf("%d\n",count(str,substr));
    return 0;
}

参考这个 https://ask.csdn.net/questions/7523308?spm=1005.2026.3001.5622

#include <stdio.h>
#include <string.h>
int totsubstrnum(char *str, char *substr);
void main()
{
    char str[80], substr[80];
    gets(str);
    gets(substr);
    int res = totsubstrnum(str, substr);
    printf("%d",res);
}
int totsubstrnum(char *str, char *substr)
{
    int n, m, count = 0, i;
    n = strlen(str);
    m = strlen(substr);
    for (i = 0; i <= n - m; i++)
    {
        if (strncmp(str + i, substr, m) == 0)
        {
            count++;
            i += m - 1;
        }
        else
            continue;
    }
    return count;
}