从键盘输入元素创建一个整形数组{1, 3,6,9},并遍历打印每个元素。
public static void main(String[] args) {
Scanner sc= new Scanner(System.in);
int a[]=new int[4];
for (int i = 0; i < 4; i++) {
a[i]=sc.nextInt();
}
for (int i = 0; i < 4; i++) {
System.out.println("第"+(i+1)+"个元素是:"+a[i]);
}
}
Scanner scanner= new Scanner(System.in);
int n=scanner.nextInt();
int[] arr = new int[n];
for(int i=0;i<n;i++){
arr[i] =scanner.nextInt();
}
for(int j=0;j<n;j++){
System.out.println(arr[i]);
}
```
import java.util.*;
public class Test {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.print("输入数组长度:");
int n = input.nextInt();
int[] a = new int[n];
System.out.print("输入数组数字:");
for(int i=0;i<n;i++){
a[i] = input.nextInt();
}
for(int i=0;i<n;i++){
System.out.println(a[i]);
}
}
}