vc++6.0求帮助

（从键盘输入若干字符，直到按回车键结束。分别统计字母字符、数字字符和其他字符的个数）大一新生

供参考：

#include <stdio.h>
#include <string.h>
int main()
{
    char c;
    int letter = 0, digit = 0, other = 0;
    printf("请输入一行字符：\n");
    while ((c = getchar()) != '\n')
    {
        if ((c >= 'a' && c <= 'z') || (c >= 'A' && c <= 'Z'))
        {
            letter++;
        }
        else if (c >= '0' && c <= '9')
        {
            digit++;
        }
        else {
            other++;
        }
    }
    printf("字母有：%d个，数字有：%d个，其他字符有：%d个\n", letter, digit, other);
    return 0;
}



#include<stdio.h>
int main(){
    char a[1024];
    int        cnt_upper = 0, cnt_lower = 0, cnt_chinese = 0, cnt_digit = 0, cnt_space = 0, cnt_others = 0;
    gets(a);

    for ( int j = 0; j < strlen(a); j++ )
    {
        if ( a[j] >= 'a' && a[j] <= 'z' )
            cnt_lower++;

        else if ( a[j] >= 'A' && a[j] <= 'Z' )
            cnt_upper++;

        else if ( a[j] >= '0' && a[j] <= '9' )
            cnt_digit++;

        else if ( a[j] == ' ' )
            cnt_space++;

        else if ( a[j] < 0 )
        {
            cnt_chinese++, j++;
        }else cnt_others++;
    }

    printf( "upper:%d\nlower:%d\nchinese:%d\ndigit:%d\nspace:%d\nothers:%d\n", cnt_upper, cnt_lower, cnt_chinese, cnt_digit, cnt_space, cnt_others );
    return 0;
}

运行结果：

img