为什么1602第二行只显示4个0？是不是需要定义一个0-9的16进制数组，把temp转化到数组里？
#include "reg52.h"
#include "xpt2046.h"
#include "lcd.h"
typedef unsigned int u16;
typedef unsigned char u8;
unsigned char code table1[] = "Voltage:";
uint temp;
sbit k1 = P3^2;
sbit relay = P3^3;
/*void delay(uint i)
{
while (i--);
} */
void datapros()
{
uint temp;
static u8 i;
if (i == 50)
{
i = 0;
temp = Read_AD_Data(0x94);
}
i++;
}
void main()
{
char i;
init1602();
datapros();
writeinstruction(0x80);
delay(5);
EA = 1;
EX0 = 1;
EX1 = 1;
for (i = 0; i < 8; ++i)
{
writedata(table1[i]);
delay(20);
}
writeinstruction(0x02);
writeinstruction(0x80 + 0x40);
delay(10);
writechar(temp);
delay(10);
/*砸瓦鲁多 */
while (1)
{
}
}
void Display()interrupt 0 using 1
{
if (k1 == 0)
delay(100);
if (k1 == 0)
{
relay=0;
delay(500);
relay = 1;
delay(100);
while (!k1);
}
}
这是1602转化ASCII码程序
void writechar(unsigned char z)
{
unsigned char A;
unsigned char B;
unsigned char C;
unsigned char D;
RS = 1;
EN = 0;
RW = 0;
A = z / 1 % 10;
B = z / 10 % 10;
C = z / 100 % 10;
D = z / 1000 % 10;
writedata(D + 48);
delay(5);
writedata(C + 48);
delay(5);
writedata(B + 48);
delay(5);
writedata(A + 48);
delay(5);
}
先要确认一下参数z的值是什么，用printf函数打印出来看看。
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