1.dupgbk.txt文件中，要统计该列表中包含的“相邻的相同元素” 的值，并将该值打印到屏幕。
(文件内容如下：
1
1
a
ssq
o
o
o
4
44
78
[1, 2]
[1, 2]
33
open
1
1
1
1
o
o
这个意思？
filename1 = dirname + '\\dupgbk.txt'
with open(filename1, 'r', encoding='utf-8') as f:
c = f.read().split("\n")
i = 0
j = 1
while i + j <= len(c):
j = 1
while i + j < len(c):
if c[i+j] ==c[i]:
j +=1
else:
break
if j != 2:
i += j
else:
print(c[i])
i = i + j
if i == len(c) - 2 and c[i] == c[i+1]:
print(c[i])
'''--result
1
[1, 2]
o
'''
filename1 = dirname + '\\dupgbk.txt'
with open(filename1, 'r', encoding='utf-8') as f:
c = f.read().split("\n")
i = 0
j = 1
while i + j <= len(c):
j = 1
while c[i+j] ==c[i]:
j +=1
if j != 1:
print(c[i])
i = i + j
else:
i += 1
if j !=1:
print(c[i])
'''--result
1
o
[1, 2]
1
o
'''
filename1 = dirname + '\\dupgbk.txt'
with open(filename1, 'r', encoding='utf-8') as f:
c = f.read().split("\n")
i = 0
j = 1
while i + j <= len(c):
j = 1
while c[i+j] ==c[i]:
j +=1
if j != 1:
print(c[i])
i = i + j
else:
print(c[i])
i += 1
if j !=1:
print(c[i])
'''--result
1
a
ssq
o
4
44
78
[1, 2]
33
open
1
o
'''
是不是1 [1,2] 0？