代码如下:
#include <iostream>
#include <string>
#include <iomanip>
using namespace std;
int main()
{
int n;
string myStr;
cin >> n;
int len = 2*(2*n-1);
for (int i = 1;i<=n;i++)
{
if(i<n)
cout << setw((len - 2*(2*i-1))/2) <<" ";
myStr ="";
for(int j = 1;j<=2*i-1;j++)
myStr += "* ";
myStr += "\n";
cout << myStr;
}
return 0;
}
你题目的解答代码如下:
#include <iostream>
#include <string>
using namespace std;
int main() {
int n;
string myStr;
cin >> n;
for (int i = 0; i < n; i++)
{
for (int j = 1; j < n-i; j++)
myStr+=" ";
for (int j = 0; j < 2*i+1; j++)
myStr+="* ";
myStr+="\n";
}
cout << myStr;
return 0;
}
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