用C语言求1~30偶数阶乘的和 求解

#include <stdio.h>
main()
{ double sum=0,t=1;
int i;
for (i=2;i<=30;i+=2);
while(i%2==0) break;
t=t*i;
sum=sum+t;

printf("sum=%e\n",sum);

}

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