windows子系统下ubuntu20.04, 使用gdb中的watch命令时，程序不中断，也不打印新旧值。
这是源码
```c
1 #include <stdio.h>
2 #include <stdlib.h>
3
4 int main()
5 {
6 int i, j, k;
7
8 i = 0;
9 j = 1;
10 k = 2;
11
12 i = j + k;
13 j = j * k;
14 k = k * j;
15
16 printf("i = %d\n",i);
17 printf("j = %d\n",j);
18 printf("k = %d\n",k);
19
20 return 0;
21 }
这是gdb
For help, type "help".
Type "apropos word" to search for commands related to "word"...
Reading symbols from test...
(gdb) b 8
Breakpoint 1 at 0x1155: file test.c, line 8.
(gdb) r
Starting program: /home/lingling/test
Breakpoint 1, main () at test.c:8
8 i = 0;
(gdb) p i
$1 = 32767
(gdb) watch i
Hardware watchpoint 2: i
(gdb) c
Continuing.
i = 3
j = 2
k = 4
Watchpoint 2 deleted because the program has left the block in
which its expression is valid.
__libc_start_main (main=0x8001149 <main>, argc=1, argv=0x7ffffffee468, init=<optimized out>, fini=<optimized out>,
rtld_fini=<optimized out>, stack_end=0x7ffffffee458) at ../csu/libc-start.c:342
342 ../csu/libc-start.c: No such file or directory.
(gdb) q
###### 运行结果及报错内容
正常说，continuing之后，应该打印旧值和新值
###### 我的解答思路和尝试过的方法
###### 我想要达到的结果
按理说应该输出
Old value=
New value=
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