用 for 循环语句求 1^2 到 n^2的和。
def s (n): s = 0 for i in range(1, n + 1): s += i ** 2 return s print(s(3))
num = input("input: ") sumNumber = 0 for i in range(1,int(num)+1): sumNumber += i**2 print(sumNumber)