编程情况，帮看一下我哪里出错了

乎乎喜欢编程，他今天计划编程t小时，计划编写n道题目，每道题需要m分钟完成。请输出题目完成情况：如果完成0道或1道题，则输出“He wrote 0 programming question, and left n programming questions for tommorrow.” 或 “He wrote 1 programming question, and left n-1 programming questions for tommorrow.”。如果完成x(x≥2)道题输出，则输出“He wrote x programming questions, and left n - x programming questions for tommorrow.

#include <stdio.h>

int main()

{

float t,x;
int n,m;

scanf("%f%d%d",&t,&n,&m);

x=(60*t)/m;

if(x<2)

    printf("He wrote 0 programming question, and left n programming questions f3or tommorrow.||He wrote 1 programming question, and left n–1 programming questions for tommorrow.",x);

if(x>=2)

    printf("He wrote %d programming question, and left n-%d programming questions for tommorrow.",x);

    return 0;

}
请问大佬，这个哪里出错了？

x=0和1你要分开写输出语句，完成1个时要提示还有n一个1个未完成。大于1时有两个%d，尔后面需要两个x。另外n不能写在字符串，要用输入的n替换啊

#include <stdio.h>
int main()
{
    int t,x,n,m;
    scanf("%d%d%d",&t,&n,&m);
   x=(60*t)/m;
   printf("He wrote %d programming question, and left %d programming questions f3or tommorrow",x,n-x);
   return 0;
}