fun623(int a,int b){return a*b;}void main(){int x=3, y=4, z=5,r;r=fun623((x--,y++,x+y),z--);printf("%d\n",r);}
逗号表达式,返回x+y的结果。x--使x=2,y++使y=5,x+y=7z--传递z=5return a * b= 7 * 5=35输出35