实现函数rnMean,该函数的功能是计算n(n<100)个有理数的平均数并返回,结果为最简分数形式。
#include
#include
using namespace std;
struct rationalNumber{
int fenzi; // 分子
int fenmu; // 分母
};
// 函数rnMean:计算n个有理数的平均数
// 参数:a-存放有理数的数组,n-有理数的个数
// 返回值:n个有理数的平均数
rationalNumber rnMean(rationalNumber a[], int n);
int main()
{
char c;
rationalNumber a[100],z;
int n, i;
// 输入有理数个数
cin >> n;
// 输入n个有理数
for(i = 0; i < n; i++)
cin >> a[i].fenzi >> c >> a[i].fenmu;
// 计算有理数平均数
z = rnMean(a,n);
// 输出平均数
if(z.fenmu == 1)
cout << z.fenzi << endl;
else
cout << z.fenzi << "/" << z.fenmu << endl;
return 0;
}
// 请在此添加代码,实现函数rnMean
/********** Begin *********/
int zdg(int a, int b)
{
int x = a % b;
while(x != 0){
a = b;
b = x;
x = a % b;
}
return b;
}
rationalNumber rnAdd(rationalNumber x, rationalNumber y)
{
rationalNumber n;
int m = zdg(x.fenmu, y.fenmu);
int u = x.fenmu * y.fenmu / m;
n.fenmu = u;
n.fenzi = x.fenzi * u / x.fenmu + y.fenzi * u / y.fenmu;
return n;
}
rationalNumber huajian(rationalNumber n)
{
int a=0, b=0;
if(n.fenzi!=0 && n.fenmu!=0){
if (fabs(n.fenzi) > fabs(n.fenmu)){
a = fabs(n.fenzi);
b = fabs(n.fenmu);
}
else{
a = fabs(n.fenmu);
b = fabs(n.fenzi);
}
int h = zdg(a,b);
if(h != 0){
n.fenzi = n.fenzi/h;
n.fenmu = n.fenmu/h;
}
else{
n.fenzi = n.fenzi;
n.fenmu = n.fenmu;
}
}
if(n.fenzi == 0)
n.fenmu = 1;
return n;
}
rationalNumber rnMean(rationalNumber a[], int n)
{
rationalNumber t = a[0];
for (int i = 1; i < n; i++)
t = rnAdd(t, a[i]);
t.fenmu = t.fenmu * n;
t = huajian(t);
return t;
}
/********** End **********/
#include "stdio.h"
#include "stdlib.h"
int gcd(int a,int b){
int c;
while(b){
c=a;
a=b;
b=c%b;
}
return a;
}
void rnMean(int * a, int * b, int n, int * c, int * d)
{
int g = 1;
if (n == 0) { *c = 0; *d = 1; return; }
for (int i = 0; i < n; i++)
{
g = g * b[i] / gcd(g, b[i]);
}
int sum = 0;
for (int i = 0; i < n; i++)
{
sum += a[i] * g / b[i];
}
int cd = gcd(sum, g);
*c = sum / cd; *d = g / cd;
}
int main()
{
int n;
printf("n=?");
scanf("%d", &n);
int * a = (int *)malloc(sizeof(int) * n);
int * b = (int *)malloc(sizeof(int) * n);
printf("format ?/?:\n");
for (int i = 0; i < n; i++)
scanf("%d/%d", &a[i], &b[i]);
int c;
int d;
rnMean(a, b, n, &c, &d);
if (d == 1)
printf("%d\n", c);
else if (c == 0)
printf("0\n");
else
printf("%d/%d\n", c, d);
return 0;
}