为什么用scrapy框架爬取tx新闻的内容，只能爬取一页的内容？

问题遇到的现象和发生背景 通过拼接网址，构造跳转网页函数，但就是不能爬取后面几页的内容

问题相关代码，请勿粘贴截图

import scrapy
import json
import requests
import re
from ..items import TencentNewsItem
from scrapy.http import Request
from lxml import etree
class NewsSpider(scrapy.Spider):
    name = 'news'

    allowed_domains = ['qq.com']



    headers = {'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/91.0.4472.77 Safari/537..36 Edg/91.0.864.37'}



    start_urls = ['https://i.news.qq.com/trpc.qqnews_web.kv_srv.kv_srv_http_proxy/list?sub_srv_id=24hours&srv_id=pc&offset=20&limit=20&strategy=1&ext={%22pool%22:[%22top%22],%22is_filter%22:7,%22check_type%22:true}']



    def parse(self, response):


        item = TencentNewsItem()

        data = response.body.decode("utf-8")

        pat1 = '"title":"(.*?)"'
        pat2 = '"url":"(.*?)"'
        pat3 = '"tag_word":"(.*?)"'
        pat4 = '"update_time":"(.*?)"'
        pat5 = '"comment_num":(.*?),'
        pat6 = '"media_name":"(.*?)"'
        pat7 = '"sub_category_cn":"(.*?)"'
        pat8 = '"category_cn":"(.*?)"'
        item["title"] = re.compile(pat1).findall(data)
        item["url"] = re.compile(pat2).findall(data)
        item["tag_word"] = re.compile(pat3).findall(data)
        item["update_time"] = re.compile(pat4).findall(data)
        item["comment_num"] = re.compile(pat5).findall(data)
        item["media_name"] = re.compile(pat6).findall(data)
        item["sub_category_cn"] = re.compile(pat7).findall(data)
        item["category_cn"] = re.compile(pat8).findall(data)
        yield item
        for i in range(0,10):
            urls = ['https://i.news.qq.com/trpc.qqnews_web.kv_srv.kv_srv_http_proxy/list?sub_srv_id=24hours&srv_id=pc&offset=' + str(
                i * 20) + '&limit=20&strategy=1&ext={%22pool%22:[%22top%22],%22is_filter%22:7,%22check_type%22:true}']
          #  urls = ['https://i.news.qq.com/trpc.qqnews_web.kv_srv.kv_srv_http_proxy/list?sub_srv_id=24hours&srv_id=pc&offset={}&limit=20&strategy=1&ext='.format(str(i)) + '{%22pool%22:[%22top%22],%22is_filter%22:2,%22check_type%22:true}']
            # '{%22pool%22:[%22top%22],%22is_filter%22:2,%22check_type%22:true}'


        for url in urls:
            yield Request(url, callback=self.parse)

运行结果及报错内容

我的解答思路和尝试过的方法

我想要达到的结果