完数及其个数代码编写

Python语言编辑求解1~1000以内的完数及其个数

def perfect(n):
    factor = []
    for i in range(1,n//2+1):
        if n%i==0:
            factor.append(i)
    if sum(factor)==n:
        return True
    else:
        return False

count = 0
for i in range(1,1001):
    if perfect(i):
        count += 1
        print(i)

6
28
496
3