id exchange
1 d:got/p:got/i:getting
2 d:got
3 s:gota
4 t:got up
5 d:appled/p:appled
6 s:appled
7 i:appled tree
8 0:appledp
9 0:appledp/i:appledping
怎样用mysql
筛选出第1,2,5,6行
但不要同时筛选出第3,4,7,8,9行
select * from table where left(exchange,5)=' d:got'
当然如果你还需要通用答案的话,可以用instr函数。
请问你的筛选依据是什么,只是行数吗?
select * from table_name where id in (1,2,5,6)
select * from table where exchange like 'd:got%' or exchange like 'd:appled%' or exchange like 's:appled%';
有用望采纳!!!