Java如何用空格做分割符但不分割[]中的空格

比如：aa bb [cc dd ee] ff
分割成
aa
bb
[cc dd ee]
ff

不存在嵌套[]，例如：aa [bb [cc dd]] ee
不存在类似左右不匹配，例如：aa bb [cc dd ee和aa bb cc] dd ee

就这样。。。

import java.util.ArrayList;
import java.util.LinkedList;
import java.util.List;
import java.util.Queue;


public class Test {
    public static void main(String[] args) throws Exception {
        String[] split = split("aa bb [cc dd ee] [ff gg] ee", " ");
        for(String s : split)
            System.out.println(s);
    }

    private static String[] split(String str, String regex) throws Exception {
        List<String> resultList = new ArrayList<>();
        if(str == null || str.isEmpty()) return resultList.toArray(new String[0]);
        String[] split = str.split(regex);
        Queue<String> queue = new LinkedList<>();
        for(String s: split){
            if(s.charAt(0) == '[' && s.charAt(s.length() - 1) == ']'){
                resultList.add(s);
                continue;
            }
            if(s.charAt(0) == '['){
                queue.offer(s);
                continue;
            }
            if(s.charAt(s.length() - 1) == ']'){
                if(queue.isEmpty())
                    throw new Exception("格式不对");
                StringBuilder sb = new StringBuilder();
                while(!queue.isEmpty()){
                    sb.append(queue.poll());
                    sb.append(" ");
                }
                sb.append(s);
                resultList.add(sb.toString());
                continue;
            }
            if(!queue.isEmpty()) queue.offer(s);
            else resultList.add(s);
        }
        return resultList.toArray(new String[0]);
    }
}

public static void main(String[] args) throws Exception {
        String str = "[aa gg ww [ff gg hh]] aa  bb [cc dd ee]  ff";
        int k = 0;
        StringBuffer sb = new StringBuffer();
        List<String> result = new ArrayList<>();
        for(int i=0;i<str.length();i++){
            char c = str.charAt(i);
            if(c == '[' || c == ']')
                k++;
            if(c == ' ' && k != 1 ){
                if(sb.length() != 0)
                    result.add(sb.toString());
                sb = new StringBuffer();
                if(k == 2)k=0;
                continue;
            }
            sb.append(c);
        }
        if(sb.length() != 0){
            result.add(sb.toString());
        }
       System.out.println(result);
    }

楼上专业啊，看到问题解决问题

public class TestDemo {

    public static void main(String[] args) {
        String str = "aa bb [cc dd ee] ff";
        String a[] = str.split(" ");
        
        String b[] = new String[4];
        b[0] = a[0];
        b[1] = a[1];
        b[2] = a[2] + " " + a[3] + " " + a[4];
        b[3] = a[5];
        for(String s : b) {
            System.out.println(s);
        }
    }
}