提取数字串数组 用atof函数

#include  <stdio.h>
#include <stdlib.h>
int main()
{
    char s[100];
    gets(s);
    double d[30],f;
    int n=0;
    int i=0,j=0;
    int flag = 1;
    while(s[i] != 0)
    {
        if((s[i]>='0' && s[i] <= '9') || s[i] == '.')
        {
            if(flag == 1)
                d[n++] = atof(s+i);
            flag = 0;
        }
        else
            flag = 1;
        i++;
    }
    for(i=0;i<n-1;i++)
        for(j=0;j<n-i-1;j++)
        {
          if(d[j] < d[j+1])
          {
              f = d[j];
              d[j] = d[j+1];
              d[j+1] = f;
          }
        }
    for(i=0;i<n;i++)
        printf("%.2lf ",d[i]);

    return 0;
}