输入5人的工资输出每个人需要1元，2元，5元，10元，20元，50元，100元，200元，500元的人民币各几张和每个种类的人民币5个人总共需要几张按下面的照片输出

代码如下，如有帮助，请帮忙采纳一下，谢谢。

#include <stdio.h>           
int main( )    
{    
    int a[5],i;
    int n[9];
    for(i=0;i<9;i++) n[i]=0;
    for(i=0;i<5;i++)
    {
        printf("Give the salary for the %d. employee > ",i+1);
        scanf("%d",&a[i]);
    }
    printf("Salary   500  200  100   50   20   10    5    2    1\n");
    for (i=0;i<5;i++)
    {
        printf("%6d   ",a[i]);
        
        printf("%3d  ",a[i]/500);
        n[0] += a[i]/500;
        printf("%3d  ",a[i]%500/200);
        n[1] += a[i]%500/200;
        printf("%3d  ",a[i]%500%200/100);
        n[2]+= a[i]%500%200/100;
        printf("%3d  ",a[i]%500%200%100/50);
        n[3]+=a[i]%500%200%100/50;
        printf("%3d  ",a[i]%500%200%100%50/20);
        n[4] += a[i]%500%200%100%50/20;
        printf("%3d  ",a[i]%500%200%100%50%20/10);
        n[5] += a[i]%500%200%100%50%20/10;
        printf("%3d  ",a[i]%500%200%100%50%20%10/5);
        n[6] += a[i]%500%200%100%50%20%10/5;
        printf("%3d  ",a[i]%500%200%100%50%20%10%5/2);
        n[7] += a[i]%500%200%100%50%20%10%5/2;
        printf("%3d\n",a[i]%2);
        n[8] += a[i]%2;
    }
    printf("Total:   ");
    for(i=0;i<9;i++)
    {
        if(i<8)
            printf("%3d  ",n[i]);
        else
            printf("%3d\n",n[i]);
    }
    return 0;       
} 

就是根据工资从最大面额开始除，除数为该种币值张数，然后用余数继续除后续币种

#include <stdio.h>
int main()
{
    int a[9] = {500,200,100,50,20,10,5,2,1};
    int b[5][9] = {0};
    int s[5];
    int i,j,sum=0;
    for(i=0;i<5;i++)
    {
        scanf("%d",&s[i]);
        for(j=0;j<9;j++)
        {
            b[i][j] = s[i]/a[j];
            money = s[i] % a[j];
        }
    }
    printf("%10s",Salary);
    for(i=0;i<9;i++)
         printf("%10d",a[i]);
    printf("\n");
    for(i=0;i<5;i++)
    {
        printf("10d",s[i]);
        for(j=0;j<9;j++)
            printf("%10d",b[i][j]);
        printf("\n");
    }
    printf("%10s","Total:");
    for(i=0;i<9;i++)
    {
        sum = 0;
        for(j=0;j<5;j++)
            sum+= b[j][i];
        printf("%10d",sum);
    }
    return 0;
}