double fz = 1.0;
#include<stdio.h> int main() { int N,i; double s; scanf("%d",&N); double fz = 1.0; for(i = 1; i <= N; i ++){ double t; t = fz / i; s += t; } printf("sum = %.6f\n", s); getchar(); return 0; } 输入6 sum = 2.450000