这个代码好像缺少返回语句但我不知道加在哪，要求先输入小于十的数字在根据这个数字输入几组数据这个好像也不行，还有那个排版要求是duo chi yu! shao chi rou!不知道在哪加换行符

    Scanner scanner = new Scanner(System.in);
    int n = scanner.nextInt();
    for(n=0;n<10;n++){
        int sex = scanner.nextInt();
        int height = scanner.nextInt();
        int weight = scanner.nextInt();
    if(sex==1)
    {
        if(height>130)
        {
            System.out.println("ni li hai!");
        }
        if(height==130)
        {
            System.out.println("wan mei!");
        }
        if(height<130)
        {
            System.out.println("duo chi yu!");
        }
        if(weight>27)
        {
            System.out.println("shao chi rou!");
        }
        if(weight==27)
        {
            System.out.println("wan mei!");
        }
        if(weight<27)
        {
            System.out.println("duo chi rou!");
        }
    }
    if(sex==0)
    {
        if(height>129)
        {
            System.out.println("ni li hai!");
        }
        if(height==129)
        {
            System.out.println("wan mei!");
        }
        if(height<129)
        {
            System.out.println("duo chi yu!");
        }
        if(weight>25)
        {
            System.out.println("shao chi rou!");
        }
        if(weight==25)
        {
            System.out.println("wan mei!");
        }
        if(weight<25)
        {
            System.out.println("duo chi rou!");
            }
        }
    }
}

}

1、不需要返回语句，启动之后控制台输入身高、体重、性别，会在控台根据你的逻辑自动输出结果；
2、由height<130 out duo chi yu! ， weight>27 out shao chi rou!
可得

if(height<130 && weight>27){
    System.out.println("duo chi yu!shao chi rou!");
}

性别=0 同理