当前页以系统当前日期的月份为准显示当前月的每一天(显示出日及对应的星期几)。当系统日期变到下一月时,系统自动翻页到下一月。 没啥思路,求大佬给点思路意见
参考如下:
#include <iostream>
using namespace std;
int main()
{
int year,mon;
int i,j,cnt = 0;
int t = 1,k=1;
int arr[]={0,31,28,31,30,31,30,31,31,30,31,30,31};
int curYear,curMon,curDay, wk;
curYear = 2021;
curMon = 10;
curDay = 27;
wk = 3;
scanf("%d %d",&year,&mon);
if(curYear > year)
{
for(i=mon;i<=12;i++)
{
if(i==2)
{
if(year%4==0 && year%100 !=0 || year%400==0)
cnt += 29;
else
cnt += 28;
}else
cnt += arr[i];
}
for(i=year+1;i<curYear;i++)
{
if(i%4==0 && i%100 !=0 || i%400==0)
cnt += 366;
else
cnt += 365;
}
for(i=1;i<curMon;i++)
{
if(i==2)
{
if(curYear%4==0 && curYear%100 !=0 || curYear%400==0)
cnt += 29;
else
cnt += 28;
}else
cnt += arr[i];
}
cnt += curDay;
wk = 7 - (wk+cnt)%7;
}else if(curYear == year)
{
if (mon > curMon)
{
for(i=curMon+1;i<mon;i++)
{
if (i==2)
{
if(curYear%4==0 && curYear%100 !=0 || curYear%400==0)
cnt += 29;
else
cnt += 28;
}else
cnt += arr[i];
}
cnt += arr[curMon] - curDay;
wk = (wk + cnt%7)%7+1;
}else if(mon == curMon)
{
wk = (wk +7- (curDay-1)%7)%7;
}else
{
for (i=mon;i<curMon;i++)
{
if(i==2)
{
if(curYear%4==0 && curYear%100 !=0 || curYear%400==0)
cnt += 29;
else
cnt += 28;
}else
cnt += arr[i];
}
cnt += curDay;
wk = (wk+7-(cnt-1)%7)%7;
}
}else
{
for(i=curMon+1;i<=12;i++)
{
if(i==2)
{
if(curYear%4==0 && curYear%100 !=0 || curYear%400==0)
cnt += 29;
else
cnt += 28;
}else
cnt += arr[i];
}
for(i=curYear+1;i<year;i++)
{
if(i%4==0 && i%100 !=0 || i%400==0)
cnt += 366;
else
cnt += 365;
}
for(i=1;i<mon;i++)
{
if(i==2)
{
if(year%4==0 && year%100 !=0 || year%400==0)
cnt += 29;
else
cnt += 28;
}else
cnt += arr[i];
}
cnt += curDay;
wk = (wk+cnt-1)%7;
}
printf("一 二 三 四 五 六 日\n");
//int t = 1,k=1;
if(year%4==0 && year%100 !=0 || year%400==0) arr[2]= 29;
while(t <= arr[mon])
{
if(k<wk)
{
printf(" ");
}else
{
printf("%-3d",t);
t++;
}
if(k%7==0) printf("\n");
k++;
}
return 0;
}