syms lamda
A = [lamda 1 1
1 lamda 1
1 1 lamda];
b = [1;lamda;lamda^2];
s = det(A);
lamdas = solve(s);
%% s ~=0 有唯一解
str = ['lamda ~= ' char(lamdas) '有唯一解'];
disp(str)
%% s = 0
for ii = 1:length(lamdas)
A1 = subs(A,lamda,lamdas(ii));
b1 = subs(b,lamda,lamdas(ii));
if rank([A1 b1]) == rank(A1)
str = ['lamda = ' char(lamdas(ii)) '有无穷多个解'];
else
str = ['lamda = ' char(lamdas(ii)) '无解'];
end
disp(str)
end
结果:
lamda ~= [-2; 1; 1]有唯一解
lamda = -2无解
lamda = 1有无穷多个解
lamda = 1有无穷多个解