alert显示undefined 要想它显示正常该怎么改



```javascript
@WebServlet(name="Form2Servlet",urlPatterns = "/form2")
public class Form2Servlet extends HttpServlet {
    protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        String enterprise=request.getParameter("enterprise");
        String phone=request.getParameter("phone");

        Message message=new Message();
        message.setCode("200");
        message.setMessage("处理成功");

        String result=JSON.toJSONString(message);
        PrintWriter out= response.getWriter();
        out.write(result);
    }

    protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {

    }
}


```javascript

<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <title>Title</title>
    <meta http-equiv="Content-Type" content="text/html;charset=UTF-8" />
    <script src="https://ajax.aspnetcdn.com/ajax/jquery/jquery-3.5.1.min.js"></script>
</head>
<body>
<form>
    <h1>
        留言
    </h1>
    企业
    <input type="text"name="enterprise" id="enterprise">
    <br>
    电话
    <input type="text" name="phone" id="phone">
    <br>
    <input type="button" onclick="send()">
</form>
<script>
    function send() {
        var enterprise=$("#enterprise").val();
        var phone=$("#phone").val();
        if(enterprise==""){
            alert("企业信息不能为空!");
            return;
        }

        $.ajax({
            url:"/form2",
            method:"post",
            data:{"enterprise":enterprise,"phone":phone},
            success:function (result){
                alert(result.message);
            },
        })

    }
</script>
</body>
</html>

我希望alert显示我输入的企业、电话信息,该怎么改动
还有alert如果显示乱码要如何改动才能显示正常

你输出一下你的result看看 里面的message在哪。 undefined就是这个字段不存在