int i,j;
int b;
int need=0;
int flag=0;
int number=0;
int a[100]={};
int reverse(int x){
if(x<0){
x *= -1;
flag=1;
}
for(i=0;x>0;i++){
a[i]=x%10;
x /=10;
number++;
}
b=number;
for(i=0;i<number;i++){
for(j=b-1;j>0;j--){
a[i] *= 10;
}
b--;
need += a[i];
}
if(flag==1){
need *= -1;
}
return need;
}
共参考:
#include <stdio.h>
int main()
{
int n, k=0, sign = 1;
scanf("%d", &n);
if (n < 0)
{
n = -n;
sign = -1;
}
while(n)
{
k = k * 10 + n % 10;
n /= 10;
}
printf("%d", sign * k);
return 0;
}