python中求列表中后一个数是前一个数的两倍的数

def doubles(lst):
    for i in range(len(lst)-1):
        if lst[i]*2==lst[i+1]:
            print(lst[i+1])

def doubles(lst):
    for i in lst:
        print(i * 2 )
def main():
    mylinst = [3,0,1,2,3,6,2,4,5,6,12]
    doubles(mylinst)
main()
```python