如下字典按照要求实现每一功能

dict1={'k1':'v1','k2':'v2','k3':'v3'}
#a
for k,v in dict1.items():
    print(k)
#b
for k,v in dict1.items():
    print(v)
#c
for k,v in dict1.items():
    print(k,v)
#d
dict1['k4']='v4'
print(dict1)
#e
del dict1['k1']
print(dict1)
#f
print(dict1['k2'])
#g
print(dict1.setdefault('k6',None))
#h
dict2={'k1':'v1','k2':'v2','k3':'v3','a':'b'}
print(dict2)

dict = {"k1":"v1", "k2":"v2", "k3":"v3"}

for key in dict.keys():
    print(key)

for value in dict.values():
    print(value)

for key, value in dict.items():
    print(key, value)


dict["k4"] = "v4"
print(dict)

dict.pop("k1")
print(dict)

print(dict["k2"])

v6 = dict.get("K6", None)
print(v6)

dict2 = {"k1":'v11', "a":"b"}
dict2.update({"k1":"v1", "k2":"v2", "k3":"v3"})
print(dict2)

dict = {"k1": "v1","k2": "v2","k3": "v3",}

for i in dict:
    print(i)
for i in dict.values():
    print(i)
for i, j in dict.items():
    print(f"K:{i} V:{j}")
dict["k4"] = "v4"
del dict['k1']
print(dict)
print(dict["k2"])
print(dict.get("k6", None))
dict2 = {"k1": "v11","a": "b",}
dict2.update(dict)
print(dict2)