c语言或c++使用一重循环求解

供参考：

#include <stdio.h>
int main()
{
    int N, M, i, cnt = 0;
    scanf("%d", &N);
    scanf("%d", &M);
    for (i = M; i <= N; i++)
        if (i % M == 0)
            cnt++;
    printf("%d", cnt);
    return 0;
}

#include <iostream>
using namespace std;
int main()
{
    int n,m;
    cin>>n;
    cin>>m;
    int count=0;
    int i=m;
    while(i<=n){
        count++;
        i+=m;
    }
    cout<<count;
    return 0;
}