计算s=1!+2!+……+n!的值
救救孩子
# include <stdio.h>
int main()
{
int i, n;
double sum = 0, s=1;
printf("请您输入n的值:\n");
scanf("%d", &n);
for(i=1; i<=n; i++)
{
s = s*i;
sum = sum + s;
}
printf("1!+2!+3!+…+n!=%22.15e\n", sum);
return 0;
}