输入x的值并要求下列函数输出x和y

#include <stdio.h>
#include <math.h>
int main()
{
    int x,y=0;
    scanf("%d",&x);
    
    switch(x)
    {
        case -2000 ... 1:
            y=x;
            break;
        case 2 ... 5:
            y=x*x+1;
            break;
        case 6 ... 9:
            y=sqrt(x+1);
            break;
        default:
            y=1/(x+1);
    }
    printf("x=%d y=%d\n",x,y);
}

#include <stdio.h>
#include <math.h>
int main()
{
    int x, t;
    double y = 0;
    scanf("%d", &x);
    t = x - 2 < 0;
    switch (t)
    {
    case 1:
        y = x;
        break;
    case 0:
        switch (x) {
        case 2:case 3:case 4:case 5:y = x * x + 1; break;
        case 6:case 7:case 8: case 9:y = sqrt(x + 1); break;
        default:y = 1 / (x + 1); break;
        }
        break;
    }
    printf("%lf", y);
    return 0;
}

 觉得有用的话采纳一下哈