如何生成这样一个矩阵
【-1 0 +1 +1 0 0 -1 -1 -1 0 0 0 +1 +1 +1 +1 0 0 0 0后面一直按规律排下去 】
用递归
function a = fun(n)
if(n==1)
a = [-1,0];
elseif(mod(n,2)==0)
a = [fun(n-1),ones(1,n),zeros(1,n)];
else
a = [fun(n-1),-ones(1,n),zeros(1,n)];
end
end
调用示例:
>> fun(3)
ans =
-1 0 1 1 0 0 -1 -1 -1 0 0 0
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